Nandrolone Phenpropionate

CAS: 62-90-8

Ref. 86-MM1786.00

Produktinformation

• Name: Nandrolone Phenpropionate
• Synonyme: 19-Norandrostenolone phenylpropionate, 19-Nortestosterone phenylpropionate, Activin (anabolic steroid), Durabol, Durabolin, Fenobolin, NPP, NSC 23162, NTPP, Nandrobolic, Nandrolin, Nandrolon phenylpropionate, Nandrolone phenylpropionate, Nerobil, Nerobolil, Norandrolone phenylpropionate, Norandrostenolone phenylpropionate, Nortestosterone phenylpropionate, Phenobolin, Strabolene, Superanabolon, Estr-4-en-3-one, 17-(1-oxo-3-phenylpropoxy)-, (17beta)-, Estr-4-en-3-one, 17beta-hydroxy-, hydrocinnamate (7CI,8CI), Estr-4-en-3-one, 17beta-hydroxy-, phenylpropionate (6CI), Hydrocinnamic acid, ester with 17beta-hydroxyestr-4-en-3-one (8CI), 17beta-(3-Phenylpropionyloxy)-estr-4-en-3-one, 17beta-Hydroxy-19-norandrost-4-en-3-one 17-phenylpropionate, 17beta-Hydroxy-4-estren-3-one17-phenylpropionate, 17beta-Hydroxyestr-4-en-3-one phenylpropionate, 19-Nor-17beta-hydroxy-3-ketoandrost-4-ene 17-phenylpropionate, (17β)-17-(1-Oxo-3-phenylpropoxy)estr-4-en-3-one, 17B-Hydroxyestr-4-En-3-One 17-(3-Phenylpropionate), 17β-(3-Phenylpropionyloxy)-estr-4-en-3-one, 17β-Hydroxy-19-norandrost-4-en-3-one 17-phenylpropionate, 17β-Hydroxy-4-estren-3-one17-phenylpropionate, 17β-Hydroxyestr-4-en-3-one phenylpropionate, 19-Nor-17β-hydroxy-3-ketoandrost-4-ene 17-phenylpropionate, 3-Oxoestr-4-En-17-Yl 3-Phenylpropanoate, Estr-4-en-3-one, 17-(1-oxo-3-phenylpropoxy)-, (17β)-, Estr-4-en-3-one, 17β-hydroxy-, hydrocinnamate, Estr-4-en-3-one, 17β-hydroxy-, phenylpropionate, Hydrocinnamic acid, ester with 17β-hydroxyestr-4-en-3-one, Nandrolone Phenypropionate, Nandrosol
• Marke: Mikromol

Chemische Eigenschaften

• Molekulargewicht: 406.56
• Formel: C₂₇H₃₄O₃
• Farbe/Form: Neat
• InChl: InChI=1S/C27H34O3/c1-27-16-15-22-21-11-9-20(28)17-19(21)8-10-23(22)24(27)12-13-25(27)30-26(29)14-7-18-5-3-2-4-6-18/h2-6,17,21-25H,7-16H2,1H3/t21-,22+,23+,24-,25-,27-/m0/s1
• InChI Key: InChIKey=UBWXUGDQUBIEIZ-QNTYDACNSA-N
• SMILES: C[C@]12CC[C@@H]3[C@H]4CCC(=O)C=C4CC[C@H]3[C@@H]1CC[C@@H]2OC(=O)CCc1ccccc1