Thiethylperazine dimaleate

CAS: 1179-69-7

Ref. TM-T17072

Produktinformation

• Name: Thiethylperazine dimaleate
• Synonyme: Toresten, Thiethylperazine maleate, Norzine, 10H-Phenothiazine, 2-(ethylthio)-10-(3-(4-methyl-1-piperazinyl)propyl)-, (Z)-2-butenedioate, 10H-Phenothiazine, 2-(ethylthio)-10-(3-(4-methyl-1-piperazinyl)propyl)-, (Z)-2-butenedioate (1:2), 10H-Phenothiazine, 2-(ethylthio)-10-[3-(4-methyl-1-piperazinyl)propyl]-, (2Z)-2-butenedioate (1:2), 2-(Ethylthio)-10-(3-(4-methyl-1-piperazinyl)propyl)phenothiazine dimaleate, 2-(Ethylthio)-10-(3-(4-methyl-1-piperazinyl)propyl)phenothiazine maleate (1:2), 2-(ethylsulfanyl)-10-[3-(4-methylpiperazin-1-yl)propyl]-10H-phenothiazine, 2-(ethylsulfanyl)-10-[3-(4-methylpiperazin-1-yl)propyl]-10H-phenothiazine di[(2Z)-but-2-enedioate], 2-Ethylmercapto-10-(3-(1-methyl-4-piperazinyl)propyl)phenothiazine dimaleate, 3-Ethylmercapto-10-(1'-methylpiperazinyl-4'-propyl)phenothiazine dimaleate, Gs-95, Norzine, Nsc-130044, Phenothiazine, 2-(ethylthio)-10-(3-(4-methyl-1-piperazinyl)propyl)-, dimaleate, Phenothiazine, 2-(ethylthio)-10-(3-(4-methyl-1-piperazinyl)propyl)-, maleate (1:2), Thiethylperazine di(hydrogen maleate), Thiethylperazine maleate [USAN], Tietylperazine malate, Tietylperazine maleate, Torecan, Torecan bimaleate, Torecan dimaleate, Torecan maleate, Toresten, Tresten, Unii-Ruk64Cf26E
• CAS: 1179-69-7

Beschreibung

Thiethylperazine dimaleate (Thiethylperazine maleate) is an antagonist of the D2 receptor and H1 receptor. Thiethylperazine dimaleate is an activator of ABCC1 and possesses antimicrobial, anti-emetic, and antipsychotic effects.

• Marke: Targetmol

Chemische Eigenschaften

• Molekulargewicht: 631.76
• Formel: C₃₀H₃₇N₃O₈S₂
• Reinheit: 99.07%
• Farbe/Form: Solid
• InChl: InChI=1S/C22H29N3S2.2C4H4O4/c1-3-26-18-9-10-22-20(17-18)25(19-7-4-5-8-21(19)27-22)12-6-11-24-15-13-23(2)14-16-24;2*5-3(6)1-2-4(7)8/h4-5,7-10,17H,3,6,11-16H2,1-2H3;2*1-2H,(H,5,6)(H,7,8)/b;2*2-1-
• InChI Key: InChIKey=RVBRTNPNFYFDMZ-SPIKMXEPSA-N
• SMILES: CCSc1ccc2c(c1)N(CCCN1CCN(C)CC1)c1ccccc1S2.O=C(O)/C=C\C(=O)O.O=C(O)/C=C\C(=O)O