Dauricine

CAS: 524-17-4

Ref. TR-D194825

Produktinformation

• Name: Dauricine
• Synonyme: [R-(R*,R*)]-4-[(1,2,3,4-Tetrahydro-6,7-dimethoxy-2-methyl-1-isoquinolinyl)methyl]-2-[4-[(1,2,3,4-tetrahydro-6,7-dimethoxy-2-methyl-1-isoquinolinyl)methyl]phenoxy]phenol, 4-[[(1R)-1,2,3,4-Tetrahydro-6,7-dimethoxy-2-methyl-1-isoquinolinyl]methyl]-2-[4-[[(1R)-1,2,3,4-tetrahydro-6,7-dimethoxy-2-methyl-1-isoquinolinyl]methyl]phenoxy]phenol,NSC 36413, 4-[(6,7-Dimethoxy-2-Methyl-1,2,3,4-Tetrahydroisoquinolin-1-Yl)Methyl]-2-{4-[(6,7-Dimethoxy-2-Methyl-1,2,3,4-Tetrahydroisoquinolin-1-Yl)Methyl]Phenoxy}Phenol, 4-[[(1R)-1,2,3,4-Tetrahydro-6,7-dimethoxy-2-methyl-1-isoquinolinyl]methyl]-2-[4-[[(1R)-1,2,3,4-tetrahydro-6,7-dimethoxy-2-methyl-1-isoquinolinyl]methyl]phenoxy]phenol, 4-{[(1R)-6,7-dimethoxy-2-methyl-1,2,3,4-tetrahydroisoquinolin-1-yl]methyl}-2-(4-{[(1R)-6,7-dimethoxy-2-methyl-1,2,3,4-tetrahydroisoquinolin-1-yl]methyl}phenoxy)phenol, Nsc 36413, Phenol, 4-((1,2,3,4-tetrahydro-6,7-dimethoxy-2-methyl-1-isoquinolinyl)methyl)-2-(4-((1,2,3,4-tetrahydro-6,7-dimethoxy-2-methyl-1-isoquinolinyl)methyl)phenoxy)-, (R-(R*,R*))-, Phenol, 4-[[(1R)-1,2,3,4-tetrahydro-6,7-dimethoxy-2-methyl-1-isoquinolinyl]methyl]-2-[4-[[(1R)-1,2,3,4-tetrahydro-6,7-dimethoxy-2-methyl-1-isoquinolinyl]methyl]phenoxy]-
• CAS: 524-17-4

Beschreibung

Applications Dauricine is a bisbenzylisoquinoline allkaloid derivative that displays a noted number of pharmaceutical properties. It is known to induces severe lung toxicity in animals.
References Xie, H. et al.: Anal. Bioanal. Chem., 408, 4111 (2016);

• Marke: TRC

Chemische Eigenschaften

• Molekulargewicht: 624.77
• Formel: C₃₈H₄₄N₂O₆
• Farbe/Form: Neat
• InChl: InChI=1S/C28H46O/c1-18(2)19(3)7-8-20(4)24-11-12-25-23-10-9-21-17-22(29)13-15-27(21,5)26(23)14-16-28(24,25)6/h7-9,18-20,22-26,29H,10-17H2,1-6H3/b8-7+/t19-,20+,22-,23-,24+,25-,26-,27-,28+/m0/s1/i9D,13D2,17D2,22D
• InChI Key: InChIKey=OILXMJHPFNGGTO-HSALZTGCSA-N
• SMILES: [2H]C1=C2C([2H])([2H])[C@@]([2H])(O)C([2H])([2H])C[C@]2(C)[C@H]2CC[C@@]3(C)[C@@H](CC[C@@H]3[C@H](C)/C=C/[C@H](C)C(C)C)[C@@H]2C1