Curcumin (Synthetic)

CAS: 458-37-7

Ref. 3B-C2302

Información del producto

• Nombre: Curcumin (Synthetic)
• Sinónimos: (E,E)-1,7-Bis(4-hydroxy-3-methoxyphenyl)-1,6-heptadiene-3,5-dione (Synthetic), (1E,4Z,6E)-5-hydroxy-1,7-bis(4-hydroxy-3-methoxyphenyl)hepta-1,4,6-trien-3-one, (1E,6E)-1,7-Bis(4-hydroxy-3-methoxyphenyl)-1,6-heptadiene-3,5-dione, (E)-1,7-Bis(4-hydroxy-3-methoxyphenyl)-1,6-heptadiene-3,5-dione, (E,E)-1,7-Bis(4-hydroxy-3-methoxyphenyl)-1,6-heptadien-3,5-dione, (E,E)-1,7-Bis(4-hydroxy-3-methoxyphenyl)-1,6-heptadiene-3,5-dione, 1,6-Heptadiene-3,5-dione, 1,7-bis(4-hydroxy-3-methoxyphenyl)-, (1E,6E)-, 1,6-Heptadiene-3,5-dione, 1,7-bis(4-hydroxy-3-methoxyphenyl)-, (E,E)-, 1,7-Bis(4-Hidroxi-3-Metoxifenil)Hepta-1,6-Dieno-3,5-Diona, 1,7-Bis(4-Hydroxy-3-Methoxyphenyl)-1,6-Heptadiene-3,5-Dione, 1,7-Bis(4-hydroxy-3-methoxyphenyl)hepta-1,6-dien-3,5-dion, 1,7-Bis(4-hydroxy-3-methoxyphenyl)hepta-1,6-diene-3,5-dione, Biocurcumax, Br 213, C Yellow 15, Colorant E 100, Curcuma, Curcuma yellow, Curcumax, Curcumin I, Curcumin W, Curcumine, Cureit, Curouma, Diferuloylmethane, E 100 (dye), E-100, E100, Gelbwurz, Haidr, Halad, Haldar, Halud, Hepta-1,6-Diene-3,5-Dione, 1,7-Bis(4-Hydroxy-3-Methoxyphenyl)- (1E,6E), INS 100i, Indian Saffron, Jianghuangsu, Kacha Haldi, Kachs Haldi, Kiriyasu Oil Yellow U, Lipocurc, Longvida, Merita Earth, NanoCurc, Natural Yellow 3, Natxtra, Nsc 32982, Safra D'Inde, San-Ei Curcumine AL, San-Ei Gen Curcumine AL, Souchet, Terra Merita, Theracurmin, Theracurmin CR 011L, Tumeric Yellow, Turmeric, Turmeric (dye), Turmeric yellow, Ukon, Ukon (dye), Vacurin, Yellow Ginger, Yellow Root, Yo-Kin, trans,trans-Curcumin
• CAS: 458-37-7
• Marca: TCI

Propiedades químicas

• Peso molecular: 368.39
• Fórmula: C₂₁H₂₀O₆
• Pureza: >97.0%(T)
• Color/Forma: Light yellow to Brown powder to crystal
• InChI: InChI=1S/C21H20O6/c1-26-20-11-14(5-9-18(20)24)3-7-16(22)13-17(23)8-4-15-6-10-19(25)21(12-15)27-2/h3-12,24-25H,13H2,1-2H3/b7-3+,8-4+
• Clave InChI: InChIKey=VFLDPWHFBUODDF-FCXRPNKRSA-N
• SMILES: COc1cc(/C=C/C(=O)CC(=O)/C=C/c2ccc(O)c(OC)c2)ccc1O