delta-Decalactone

CAS: 705-86-2

Ref. TR-D212350

Información del producto

• Nombre: delta-Decalactone
• Sinónimos: Tetrahydro-6-pentyl-2H-pyran-2-one, δ-Hydroxy-capric Acid Lactone, (RS)-δ-Decalactone, (±)-5-Hydroxydecanoic Acid Lactone, (±)-δ-Decanolactone, 5-Decanolide, 5-Hydroxydecanoic Acid δ-Lactone, 5-Pentyl-5-pentanolide, 6-Pentyltetrahydro-2H-pyran-2-one, Dihydrojasmin Lactone, δ-Amyl-δ-valerolactone, δ-Amylvalerolactone, δ-Decane Lactone, δ-Decanolactone, δ-Pentyl-δ-valerolactone, (6R)-6-pentyltetrahydro-2H-pyran-2-one, (6S)-6-pentyltetrahydro-2H-pyran-2-one, (±)-5-Hydroxydecanoic acid lactone, 2H-Pyran-2-one, tetrahydro-6-pentyl-, 5-Hydroxydecanoic acid δ-lactone, 5-Hydroxydecanoic acid, delta-lactone, 6-pentyltetrahydro-2H-pyran-2-one, Capric acid, δ-hydroxy-, lactone, Decanoic acid, 5-hydroxy-, δ-lactone, Decanolide-1,5, Delta-Decalactona, Delta-Decalactone, Delta-amyl-delta-valerolactone, Dihydrojasmin lactone, Tetrahydro-6-pentyl-2H-Pyran-2-one, delta-Decalactone~5-Hydroxydecanoic acid delta lactone, Δ-Decanolide, δ-Decane lactone
• CAS: 705-86-2

Descripción

Applications δ-Decalactone is a naturally occurring cyclic ester used by food and flavor industries for its coconut fragrance and taste. It is also used as a reagent in the synthesis of (±)-Massoilactone (M197600); a chemical component with antibacterial activity found in volatile oils.
References Schneiderman, D.K., et al.: J. Chem. Educ., 91, 131 (2014); Rali, T., et al.: Molecules, 12, 149 (2007); Zhao, J., et al.: Nat. Prod. Commun., 4, 1491 (2009); Jin, Z., et al.: Med. Plant, 3, 45 (2012)

• Marca: TRC

Propiedades químicas

• Peso molecular: 170.25
• Fórmula: C₁₀H₁₈O₂
• Color/Forma: Neat
• InChI: InChI=1S/C31H48O6/c1-17(2)9-8-10-20(28(35)36)26-22-15-24(34)27-29(5)13-12-23(33)18(3)21(29)11-14-30(27,6)31(22,7)16-25(26)37-19(4)32/h9,18,21-25,27,33-34H,8,10-16H2,1-7H3,(H,35,36)/b26-20-/t18-,21-,22-,23+,24+,25-,27-,29-,30-,31-/m0/s1
• Clave InChI: InChIKey=IECPWNUMDGFDKC-MZJAQBGESA-N
• SMILES: CC(=O)O[C@H]1C[C@@]2(C)[C@@H](C[C@@H](O)[C@H]3[C@@]4(C)CC[C@@H](O)[C@@H](C)[C@@H]4CC[C@@]32C)/C1=C(\CCC=C(C)C)C(=O)O