(2E)-Demethoxy Curcumin

CAS: 22608-11-3

Ref. TR-D230815

Información del producto

• Nombre: (2E)-Demethoxy Curcumin
• Sinónimos: 1,6-Heptadiene-3,5-dione, 1-(4-hydroxy-3-methoxyphenyl)-7-(4-hydroxyphenyl)-, (E,E)-, 1,6-Heptadiene-3,5-dione, 1-(4-hydroxy-3-methoxyphenyl)-7-(p-hydroxyphenyl)- (8CI), (1E,6E)-1-(4-Hydroxy-3-methoxyphenyl)-7-(4-hydroxyphenyl)-1,6-heptadiene-3,5-dione, (1E,6E)-1-(4-Hydroxyphenyl)-7-(4-hydroxy-3-methoxyphenyl)-1,6-heptadiene-3,5-dione, Curcumin II, Demethoxycurcumin, Desmethoxycurcumin, Monodemethoxycurcumin,Demethoxycurcumin, E,E-Desmethoxycurcumin, 1,6-Heptadiene-3,5-dione, 1-(4-hydroxy-3-methoxyphenyl)-7-(4-hydroxyphenyl)-, (1E,6E)-, 1,6-Heptadiene-3,5-dione, 1-(4-hydroxy-3-methoxyphenyl)-7-(4-hydroxyphenyl)-, (E,E)-, 1,6-Heptadiene-3,5-dione, 1-(4-hydroxy-3-methoxyphenyl)-7-(p-hydroxyphenyl)- (8CI), (1E,6E)-1-(4-Hydroxy-3-methoxyphenyl)-7-(4-hydroxyphenyl)-1,6-heptadiene-3,5-dione, (1E,6E)-1-(4-Hydroxyphenyl)-7-(4-hydroxy-3-methoxyphenyl)-1,6-heptadiene-3,5-dione, Curcumin II, Demethoxycurcumin, Desmethoxycurcumin, Monodemethoxycurcumin, 1,6-Heptadiene-3,5-dione, 1-(4-hydroxy-3-methoxyphenyl)-7-(4-hydroxyphenyl)-
• Marca: TRC
• Descripción: Applications The demethoxy derivative of Curcumin (C838500) that regulates anti-inflammatory and anti-proliferative responses through a ROS-independent mechanism. It attenuates the Wnt/β-catenin pathway through down-regulation of the transcriptional coactivator p300. Not a dangerous good if item is equal to or less than 1g/ml and there is less than 100g/ml in the packageReferences Ryu, M.J. et al.: Biochem. Biophys. Res. Comm., 377, 1304 (2008); Sandur, S.K. et al.: Carcinogenesis, 28, 1765 (2007); Huang, T. et al.: J. Agric. Food. Chem., 58, 10639 (2010)

Propiedades químicas

• Peso molecular: 338.35
• Fórmula: C₂₀H₁₈O₅
• Color/Forma: Pink To Red
• InChI: InChI=1S/C20H18O5/c1-25-20-12-15(6-11-19(20)24)5-10-18(23)13-17(22)9-4-14-2-7-16(21)8-3-14/h2-12,21,24H,13H2,1H3/b9-4+,10-5+
• Clave InChI: InChIKey=HJTVQHVGMGKONQ-LUZURFALSA-N
• SMILES: COc1cc(/C=C/C(=O)CC(=O)/C=C/c2ccc(O)cc2)ccc1O