1,2-Dioleoyl-sn-glycero-3-phosphocholine

CAS: 4235-95-4

Ref. TR-D493605

Información del producto

• Nombre: 1,2-Dioleoyl-sn-glycero-3-phosphocholine
• Sinónimos: 3,5,9-Trioxa-4-phosphaheptacos-18-en-1-aminium, 4-hydroxy-N,N,N-trimethyl-10-oxo-7-[(1-oxo-9-octadecenyl)oxy]-, hydroxide,inner salt, 4-oxide, [R-(Z,Z)]-, 3,5,9-Trioxa-4-phosphaheptacos-18-en-1-aminium, 4-hydroxy-N,N,N-trimethyl-10-oxo-7-[[(9Z)-1-oxo-9-octadecenyl]oxy]-,inner salt, 4-oxide, (7R,18Z)- (9CI), Choline phosphate, 3-ester with L-1,2-diolein (6CI), Choline, hydroxide, dihydrogen phosphate, inner salt, ester withL-1,2-diolein (8CI), Olein, 1,2-di-, L-, dihydrogen phosphate, monoester with choline hydroxide (8CI), 1,2-Dioleoyl-3-sn-phosphatidylcholine, 1,2-Dioleoyl-L-a-lecithin, 1,2-Dioleoyl-sn-glycero-3-phosphorylcholine, 1,2-Dioleoyl-sn-phosphatidylcholine, 3,5,9-Trioxa-4-phosphaheptacos-18-en-1-aminium, 4-hydroxy-N,N,N-trimethyl-10-oxo-7-[(1-oxo-9-octadecenyl)oxy]-, inner salt, 4-oxide, [R-(Z,Z)]-, DOPC, Dioleoyl L-a-lecithin, Dioleoyl-3-sn-phosphatidylcholine, Dioleoyl-L-a-glycerophosphocholine, Dioleoyl-L-a-glycerophosphorylcholine, Dioleoyl-L-a-phosphatidylcholine, Dioleoylphosphatidylcholine, L-Dioleoyl lecithin, L-a-Di(cis-9-octadecanoyl) lecithin, L-a-Dioleoyl phosphatidylcholine, L-a-Dioleoyllecithin, L-a-Dioleylphosphatidylcholine, PDD 111, sn-3-Dioleoyllecithin
• Marca: TRC
• Descripción: Stability Hygroscopic, Light SensitiveApplications 1,2-Dioleoyl-sn-glycero-3-phosphocholine is used in the generation of micelles and liposomes.References Høyrup, P., et al.: Biochim. Biophys. Acta, 1515, 133 (2001); Heberle, F., et al.: Cold Spring Harb Perspect Biol., 3, 1 (2011)

Propiedades químicas

• Peso molecular: 786.11
• Fórmula: C₄₄H₈₄NO₈P
• Color/Forma: Neat
• InChI: InChI=1S/C44H84NO8P/c1-6-8-10-12-14-16-18-20-22-24-26-28-30-32-34-36-43(46)50-40-42(41-52-54(48,49)51-39-38-45(3,4)5)53-44(47)37-35-33-31-29-27-25-23-21-19-17-15-13-11-9-7-2/h20-23,42H,6-19,24-41H2,1-5H3/b22-20-,23-21-/t42-/m1/s1
• SMILES: CCCCCCCC/C=C\CCCCCCCC(=O)OCC(COP(=O)([O-])OCC[N+](C)(C)C)OC(=O)CCCCCCC/C=C\CCCCCCCC