Pigment Orange 64

CAS : 72102-84-2

Ref. 3D-FP167567

Informations sur le produit

• Nom: Pigment Orange 64
• Synonymes: 12760, 2,4,6(1H,3H,5H)-Pyrimidinetrione, 5-[(2,3-dihydro-6-methyl-2-oxo-1H-benzimidazol-5-yl)azo]-, 2,4,6(1H,3H,5H)-Pyrimidinetrione, 5-[2-(2,3-dihydro-6-methyl-2-oxo-1H-benzimidazol-5-yl)diazenyl]-, 5-[(2,3-dihydro-6-methyl-2-oxo-1H-benzimidazol-5-yl)azo]-2,4,6(1H,3H,5H-)Pyrimidinetrione, 5-[2-(2,3-Dihydro-6-methyl-2-oxo-1H-benzimidazol-5-yl)diazenyl]-2,4,6(1H,3H,5H)-pyrimidinetrione, 5-[2-(6-methyl-2-oxo-2H-benzimidazol-5-yl)hydrazino]pyrimidine-2,4,6(1H,3H,5H)-trione, Cromophtal Orange GL, Cromophtal Orange GP, Cromophtal Orange K 2960, Microlen Orange GP-MP, P.O.64, PV Fast Orange H 2GL, PV Fast Orange H 2GL-VP3044, Po 64, Tco 06401, C.I.Pigment Orange 64, C.I. Pigment Orange 64

Description

Pigment Orange 64 is an organic solvent that can be used as a polymerization initiator. Pigment Orange 64 has been extensively used in the production of polyester, polyurethane, and epoxy resins. It is also used as a colorant in paints and textiles. Pigment Orange 64 can be detected using high-performance liquid chromatography (HPLC) with detection sensitivity of 0.01 ppm. The skeleton of Pigment Orange 64 consists of a hydrophobic benzene ring with two hydroxyl groups on either side and two double bonds on each end. It has four functional groups: a carboxylic acid group, an aromatic ring, a phenol group, and an alcohol group. Pigment Orange 64 is soluble in water to form orange solutions and can be detected by its characteristic odor. In addition, it can act as a matrix polymer for metal particles due to its basic properties.

• Marque: Biosynth

Propriétés chimiques

• Masse moléculaire: 302.25 g/mol
• Formule: C₁₂H₁₀N₆O₄
• Degré de pureté: Min. 95%
• Couleur/Forme: Powder
• InChI: InChI=1S/C12H10N6O4/c1-4-2-6-7(14-11(21)13-6)3-5(4)17-18-8-9(19)15-12(22)16-10(8)20/h2-3,8H,1H3,(H2,13,14,21)(H2,15,16,19,20,22)/b18-17+
• Code InChI: InChIKey=RITYHZCLJGBCAJ-ISLYRVAYSA-N
• SMILES: Cc1cc2[nH]c(=O)[nH]c2cc1/N=N/C1C(=O)NC(=O)NC1=O