Acetophenazine Maleate

CAS : 5714-00-1

Ref. 86-MM1725.00

Informations sur le produit

• Nom: Acetophenazine Maleate
• Synonymes: Ethanone, 1-[10-[3-[4-(2-hydroxyethyl)-1-piperazinyl]propyl]-10H-phenothiazin-2-yl]-, (2Z)-2-butenedioate (1:2)Ethanone, 1-[10-[3-[4-(2-hydroxyethyl)-1-piperazinyl]propyl]-10H-phenothiazin-2-yl]-, (2Z)-2-butenedioate (1:2) (salt) (9CI), Ethanone, 1-[10-[3-[4-(2-hydroxyethyl)-1-piperazinyl]propyl]-10H-phenothiazin-2-yl]-, (Z)-2-butenedioate (1:2) (salt), Ketone, 10-[3-[4-(2-hydroxyethyl)-1-piperazinyl]propyl]phenothiazin-2-yl methyl, dimaleate (6CI), Ketone, 10-[3-[4-(2-hydroxyethyl)-1-piperazinyl]propyl]phenothiazin-2-yl methyl, maleate (1:2) (salt) (8CI), Ketone, 10-[3-[4-(2-hydroxyethyl)-1-piperazinyl]propyl]phenothiazin-2-yl methyl, maleate (7CI), Acetophenazine dimaleate, NSC 169180, NSC 70600, Phentoxate, Sch 6673, Tindal, Tindala, 1-(10-{3-[4-(2-hydroxyethyl)piperazin-1-yl]propyl}-10H-phenothiazin-2-yl)ethanone di[(2Z)-but-2-enedioate] (salt), Acephenazine dimaleate, Acetophenazine maleate, Ethanone, 1-[10-[3-[4-(2-hydroxyethyl)-1-piperazinyl]propyl]-10H-phenothiazin-2-yl]-, (2Z)-2-butenedioate (1:2), Ethanone, 1-[10-[3-[4-(2-hydroxyethyl)-1-piperazinyl]propyl]-10H-phenothiazin-2-yl]-, (2Z)-2-butenedioate (1:2) (salt), Ethanone, 1-[10-[3-[4-(2-hydroxyethyl)-1-piperazinyl]propyl]-10H-phenothiazin-2-yl]-, (Z)-2-butenedioate (1:2) (salt), Ketone, 10-[3-[4-(2-hydroxyethyl)-1-piperazinyl]propyl]phenothiazin-2-yl methyl, dimaleate, Ketone, 10-[3-[4-(2-hydroxyethyl)-1-piperazinyl]propyl]phenothiazin-2-yl methyl, maleate, Ketone, 10-[3-[4-(2-hydroxyethyl)-1-piperazinyl]propyl]phenothiazin-2-yl methyl, maleate (1:2) (salt)
• CAS: 5714-00-1
• Marque: Mikromol

Propriétés chimiques

• Masse moléculaire: 643.70
• Formule: C₂₃H₂₉N₃O₂SC₄H₄O₄
• Couleur/Forme: Neat
• InChI: 2*5-3(6)1-2-4(7)8/h2-3,5-8,17,27H,4,9-16H2,1H3, 2*2-1-, InChI=1S/C23H29N3O2S.2C4H4O4/c1-18(28)19-7-8-23-21(17-19)26(20-5-2-3-6-22(20)29-23)10-4-9-24-11-13-25(14-12-24)15-16-27, 2*1-2H,(H,5,6)(H,7,8)/b
• SMILES: CC(=O)c1ccc2c(c1)N(CCCN1CCN(CCO)CC1)c1ccccc1S2.O=C(O)/C=C\C(=O)O.O=C(O)/C=C\C(=O)O