11-Dehydro Thromboxane B2 (85%)

CAS: 67910-12-7

Rif. TR-D230555

Informazioni sul prodotto

• Nome: 11-Dehydro Thromboxane B2 (85%)
• Sinonimi: (5Z)-7-[(2R,3S,4S)-Tetrahydro-4-hydroxy-2-[(1E,3S)-3-hydroxy-1-octen-1-yl]-6-oxo-2H-pyran-3-yl]-5-heptenoic Acid, 11-Dehydro-TXB2, 11-keto-Thromboxane B2, (5Z,9α,13E,15S)-9,15-Dihydroxy-11-oxo-thromboxa-5,13-dien-1-oic Acid, [2R-[2α(1E,3S*),3β(Z),4β]]-7-[Tetrahydro-4-hydroxy-2-(3-hydroxy-1-octenyl)-6-oxo-2H-pyran-3-yl] 5-Heptenoic Acid, (5Z)-7-[(2R,3S,4S)-Tetrahydro-4-hydroxy-2-[(1E,3S)-3-hydroxy-1-octen-1-yl]-6-oxo-2H-pyran-3-yl]-5-heptenoic acid, 11-Dehydrothromboxane B₂, 11-keto-Thromboxane B₂, 5-Heptenoic acid, 7-((2R,3S,4S)-tetrahydro-4-hydroxy-2-((1E,3S)-3-hydroxy-1-octenyl)-6-oxo-2H-pyran-3-yl)-, (5Z)-, 5-Heptenoic acid, 7-[(2R,3S,4S)-tetrahydro-4-hydroxy-2-[(1E,3S)-3-hydroxy-1-octen-1-yl]-6-oxo-2H-pyran-3-yl]-, (5Z)-, 5-Heptenoic acid, 7-[tetrahydro-4-hydroxy-2-(3-hydroxy-1-octenyl)-6-oxo-2H-pyran-3-yl], [2R-[2α(1E,3S*),3β(Z),4β]]-, Thromboxa-5,13-dien-1-oic acid, 9,15-dihydroxy-11-oxo-, (5Z,9alpha,13E,15S)-, Thromboxa-5,13-dien-1-oic acid, 9,15-dihydroxy-11-oxo-, (5Z,9α,13E,15S)-, 11-Dehydrothromboxane B2

Descrizione

Applications A metabolite of Thromboxane that is an in vivo markers of oxidative stress and platelet activation. It is associated with adverse cardiovascular events in Alzheimer's Disease Anti-inflammatory Prevention Trial (ADAPT).
References Santilli, F. et al.: J. Am. Coll. Cardiol., 47, 391 (2006); Montine, T.J. et al.: PLoS One, 5, No pp given (2010); Boehm, E. et al.: J. Biol. Chem., 279, 7663 (2004);

• Marchio: TRC

Proprietà chimiche

• Peso molecolare: 368.46
• Formula: C₂₀H₃₂O₆
• Purezza: 85%
• Colore/Forma: Colourless to Pale Yellow Thick Oil
• InChI: InChI=1S/C20H32O6/c1-2-3-6-9-15(21)12-13-18-16(17(22)14-20(25)26-18)10-7-4-5-8-11-19(23)24/h4,7,12-13,15-18,21-22H,2-3,5-6,8-11,14H2,1H3,(H,23,24)/b7-4-,13-12+/t15-,16-,17+,18+/m0/s1
• InChI key: InChIKey=KJYIVXDPWBUJBQ-UHHGALCXSA-N
• SMILES: CCCCC[C@H](O)/C=C/[C@H]1OC(=O)C[C@H](O)[C@@H]1C/C=C\CCCC(=O)O