Disperse Blue 60 (Technical Grade)

CAS: 12217-80-0

Rif. TR-D493558

Informazioni sul prodotto

• Nome: Disperse Blue 60 (Technical Grade)
• Sinonimi: 4,11-Diamino-2-(3-methoxypropyl)-1H-naphth[2,3-f]isoindole-1,3,5,10(2H)-tetrone, 2,3-Anthracenedicarboximide, 1,4-diamino-9,10-dihydro-N-(3-methoxypropyl)-9,10-dioxo- (7CI), 2,3-Anthraquinonedicarboximide, 1,4-diamino-N-(3-methoxypropyl)- (6CI), 4,11-Diamino-2-(3-methoxypropyl)-1H-naphth[2,3-f]isoindole-1,3,5,10(2H)-tetrone (ACI), C.I. Disperse Blue 60 (8CI), B 60, C.I. 61104, C.I. Disperse Blue 99, Dianix Turquoise Blue S-BG, Disperse Blue 60, Disperse Blue 99, Disperse Turquoise Blue 60, Disperse Turquoise Blue GL, Disperse Turquoise Blue S-GL, Genacron Brilliant Blue 8G, Kayalon Polyester Turquoise Blue GGF, Kayalon Polyester Turquoise Blue GL-S, Kayalon Polyester Turquoise Blue GL-S 200%, Kayaset B 766, Latyl Brilliant Blue BG, Miketon Polyester Brilliant Blue BG, Palanil Brilliant Blue BG, Palanil Brilliant Blue BG-M, Polycron Turquoise Blue GLP, Qualsperse Blue BNS, Resolin Brilliant Blue BGL, Resolin Brilliant Blue BGL 200, Samaron Blue FFBL, Samaron Brilliant Blue R-GL, Serilene Brilliant Blue 2GN, Sodyecron Brilliant Blue BGE 200, Sumikaron Turquoise Blue G, Sumikaron Turquoise Blue S-GL, Sumikaron Turquoise Blue S-GL 200, Sumikaron Turquoise Blue S-GL double liquid, Sumikaron Turquoise Blue S-GLF, Sumiplast Turquoise Blue G, Synten Blue P-BGFN, Terasil Blue BGE, Terasil Blue BGE 01, Terasil Blue BGE 01-200, Terasil BR Blue BGE 200-017, Terasil Brilliant Blue BGE, Teratop Blue BGE, Tersetile Turquoise GL, TS Turquoise Blue 606
• Marchio: TRC
• Descrizione: Applications Disperse Blue 60 (cas# 12217-80-0) is a compound useful in organic synthesis.

Proprietà chimiche

• Peso molecolare: 379.37
• Formula: C₂₀H₁₇N₃O₅
• Colore/Forma: Neat
• InChI: InChI=1S/C20H17N3O5/c1-28-8-4-7-23-19(26)13-14(20(23)27)16(22)12-11(15(13)21)17(24)9-5-2-3-6-10(9)18(12)25/h2-3,5-6H,4,7-8,21-22H2,1H3
• InChI key: InChIKey=FMMBXHIYUAPYRP-UHFFFAOYSA-N
• SMILES: NCCNc1cccc2c1C(=O)N(C1CCC(=O)NC1=O)C2=O.O=[C]C(F)(F)F