Dichloro(cycloocta-1,5-diene)ruthenium(II), polymer

CAS: 50982-12-2

Ref. 3D-FD138997

Product Information

• Name: Dichloro(cycloocta-1,5-diene)ruthenium(II), polymer
• Synonyms: (1,5-Cyclooctadiene)dichlororuthenium homopolymer, (1Z,5Z)-cycloocta-1,5-diene, 1,5-Cyclooctadiene, ruthenium complex, 1,5-Cyclooctadienedichlororuthenium, Cyclooctadieneruthenium dichloride, Dichloro((1,2,5,6-eta)-cycloocta-1,5-diene)ruthenium, Dichloro(1,5-cyclooctadien)ruthenium(II) polymer, Dichloro(1,5-cyclooctadiene)ruthenium, Dichloro(1,5-cyclooctadiene)ruthenium(II), Dichloro(1,5-cyclooctadiene)ruthenium(II) polymer, Dichloro(Cycloocta-1,5-Diene)Ruthenium(Ii), Dichloro(cycloocta-1,5-diene)ruthenium(II)polymer, Dichloro(cyclooctadiene)ruthenium, Dichloro[(1,2,5,6-Η)-1,5-Cyclooctadiene]Ruthenium, Dichlororuthenium, NSC 71324, Ruthenium(II) chloride 1,5-cyclooctadiene complex, Ruthenium, dichloro(1,5-cyclooctadiene)-, Ruthenium, dichloro[(1,2,5,6-η)-1,5-cyclooctadiene]-, ruthenium(2+) dichloride-(1Z,5Z)-cycloocta-1,5-diene (1:1)
• CAS: 50982-12-2

Description

Dichloro(cycloocta-1,5-diene)ruthenium(II), polymer (RuCl2(COD)) is a coordination compound that belongs to the group of metal complexes. It is a coordination polymer with alternating single and double bonds between cyclooctadiene rings and ruthenium centers. The RuCl2(COD) complex has a square planar geometry, with the chloride ligands occupying one of the corners. The polymer exhibits bond cleavage reactions, which are characteristic of chloro compounds. It also undergoes oxidation reactions and can be reduced to the corresponding dichloride by sodium thiosulfate. Crystallography studies have shown that RuCl2(COD) has an orange-brown powder color, with one crystalline form in hexagonal space group P6222.

• Brand: Biosynth

Chemical properties

• Molecular weight: 280.16 g/mol
• Formula: C₈H₁₂Cl₂Ru
• Purity: Min. 95%
• InChI: InChI=1S/C8H12.2ClH.Ru/c1-2-4-6-8-7-5-3-1;;;/h1-2,7-8H,3-6H2;2*1H;/q;;;+2/p-2/b2-1-,8-7-
• InChI key: InChIKey=DMRVBCXRFYZCPR-PHFPKPIQSA-L
• SMILES: C1=C\CC/C=C\CC/1.Cl[Ru]Cl